| What is the average force F with which a drop hammer of weight W that falls through a distance h strikes the work, if it compresses it by amount d. 
 F= Wh/d : where h and d are the units of measurement
 
 W=500 lbs
 h= 4 feet=48 inches
 d= compression of struck material (lets assume .25 inches)
 
 F=500*48/.25=96000 pounds
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